I got bored so I did an exercise from The C Programming Language, exercise 2-3 to be exact:
#include <stdio.h> int htoi(char s[]); int main() { char hexNum[] = "0x43fa"; char hexNum2[] = "0xfa"; char hexNum3[] = "0xa"; char hexNum4[] = "0x0"; printf("The value %s converted to %d\n", hexNum, htoi(hexNum)); printf("The value %s converted to %d\n", hexNum2, htoi(hexNum2)); printf("The value %s converted to %d\n", hexNum3, htoi(hexNum3)); printf("The value %s converted to %d\n", hexNum4, htoi(hexNum4)); return 0; } int htoi(char s[]) { int i = 0,n = 0,t = 0; for(i = 0; s[i] != '\0'; i++) { t = 0; if(s[i] >= '0' && s[i] <= '9' && i != 0) { t = s[i] - '0'; n = (16 * n) + t; } else if (s[i] >= 'a' && s[i] <= 'f') { t = 10 + (s[i] - 'a'); n = (16 * n) + t; } else if (s[i] >= 'A' && s[i] <= 'F') { t = 10 + (s[i] - 'A'); n = (16 * n) + t; } } return n; }